...
https://leetcode.com/problems/sort-the-matrix-diagonally/description/
– 剩下 2 题
Status | ||||
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Code Block | ||
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func diagonalSort(mat [][]int) [][]int {
m, n := len(mat), len(mat[0])
diagonals := make(map[int][]int, m+n-1)
for i := range mat {
for j, v := range mat[i] {
diagonals[j-i] = append(diagonals[j-i], v)
}
}
for _, v := range diagonals {
sort.Slice(v, func(i, j int) bool {
return v[i] >= v[j]
})
}
for i := range mat {
for j := range mat[i] {
v := diagonals[j-i][len(diagonals[j-i])-1]
diagonals[j-i] = diagonals[j-i][:len(diagonals[j-i])-1]
mat[i][j] = v
}
}
return mat
} |
LC 1260. Shift 2D Grid 二维网格迁移
https://leetcode.com/problems/shift-2d-grid/
Code Block | ||
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| ||
func shiftGrid(grid [][]int, k int) [][]int {
m, n := len(grid), len(grid[0])
total := m*n
all := make([]int, total)
for i := range grid {
for j, v := range grid[i] {
all[(i*n+j+k) % total] = v
}
}
for i := range grid {
for j := range grid[i] {
grid[i][j] = all[i*n+j]
}
}
return grid
} |
不引入额外空间做法
Status | ||||
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|
Code Block | ||
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| ||
func shiftGrid(grid [][]int, k int) [][]int {
m, n := len(grid), len(grid[0])
k = k % (m*n)
reverse(grid, 0, m*n-1)
reverse(grid, 0,k-1)
reverse(grid, k, m*n-1)
return grid
}
func reverse(grid [][]int, start, end int) {
i, j := start, end
for i < j {
a := get(grid, i)
b := get(grid, j)
set(grid, j, a)
set(grid, i, b)
i++
j--
}
}
func set(grid [][]int, index int, newValue int) {
n := len(grid[0])
i, j := index / n, index % n
grid[i][j] = newValue
}
func get(grid [][]int, index int) int {
n := len(grid[0])
i, j := index / n, index % n
return grid[i][j]
} |