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Table of Contents
stylenone

LC 26. Remove Duplicates from Sorted Array 删除有序数组中的重复项

https://leetcode.com/problems/remove-duplicates-from-sorted-array/

Code Block
languagego
func removeDuplicates(nums []int) int {
    i := 0
    j := 1
    
    for ; j < len(nums); j++ {
        if nums[j] == nums[j-1] {
            // duplicate
            continue
        }
        
        nums[i+1] = nums[j]
        i++
    }
    
    return i+1
}

另一种解法:思路类似,但是代码组织形式不同另一种解法:思路类似,只是代码组织形式不同

Code Block
languagego
func removeDuplicates(nums []int) int {
    slow, fast := 0, 0
    
    for fast < len(nums) {
        if nums[fast] != nums[slow] {
            slow++
            nums[slow] = nums[fast]
        }
        
        fast++
    }
    
    return slow+1
}

LC 83. Remove Duplicates from Sorted List 删除排序链表中的重复元素

https://leetcode.com/problems/remove-duplicates-from-sorted-list/

Code Block
languagego
/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func deleteDuplicates(head *ListNode) *ListNode {
    if head == nil {
        return nil
    }
    
    slow, fast := head, head
    for fast != nil {
        if slow.Val != fast.Val {
            slow.Next = fast
            slow = slow.Next
        }
        
        fast = fast.Next
    }
    
    slow.Next = nil
    return head
}

注意:数组版本保证至少有一个元素,而链表版本并没有保证,所以链表版本的代码需要判断是否为空(否则会空指针异常)

LC 27. Remove Element 移除元素

https://leetcode.com/problems/remove-element/

Code Block
languagego
func removeElement(nums []int, val int) int {
    slow, fast := 0, 0
    for ; fast < len(nums); fast++ {
        if nums[fast] != val {
            nums[slow] = nums[fast]
            slow++
        }
    }
    return slow
}

LC 283. Move Zeroes 移动零

https://leetcode.com/problems/move-zeroes/

Code Block
languagego
func moveZeroes(nums []int)  {
    slow, fast := 0, 0
    for ; fast < len(nums); fast++ {
        if nums[fast] != 0 {
            nums[slow] = nums[fast]
            slow++
        }
    }
    for i := slow; i < len(nums); i++ {
        nums[i] = 0
    }
}

其实和上面的「移除元素」一样,只不过不是返回 slow 而是把 nums[slow..] 赋值为 0

Code Block
languagego
func moveZeroes(nums []int)  {
    x := removeElement(nums, 0)
    for i := x; i < len(nums); i++ {
        nums[i] = 0
    }
}

func removeElement(nums []int, val int) int {
    slow, fast := 0, 0
    for ; fast < len(nums); fast++ {
        if nums[fast] != val {
            nums[slow] = nums[fast]
            slow++
        }
    }
    return slow
}

LC 167. Two Sum II - Input Array Is Sorted 两数之和 II - 输入有序数组

https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/

Code Block
languagego
func twoSum(nums []int, target int) []int {
    i, j := 0, len(nums) - 1
    for i < j {
        if nums[i] + nums[j] == target {
            return []int{i + 1, j + 1}
        } else if nums[i] + nums[j] < target {
            i++
        } else {
            j--
        }
    }
    
    return nil // impossible
}

注意返回的 index 是 1-based

LC 344. Reverse String 反转字符串

https://leetcode.com/problems/reverse-string/

Code Block
languagego
func reverseString(s []byte)  {
    i, j := 0, len(s)-1
    for i < j {
        s[i], s[j] = s[j], s[i]
        i++
        j--
    }
}

LC 5. Longest Palindromic Substring 最长回文子串

https://leetcode.com/problems/longest-palindromic-substring/

Code Block
languagego
func longestPalindrome(s string) string {
    result := ""
    
    for i := 0; i < len(s); i++ {
        ps := longestPalindrome1(s, i)
        if len(ps) > len(result) {
            result = ps
        }
    }
    
    for i := 0; i < len(s)-1; i++ {
        ps := longestPalindrome2(s, i, i+1)
        if len(ps) > len(result) {
            result = ps
        }
    }
    
    return result
}

func longestPalindrome1(s string, center int) string {    
    i, j := center, center
    for i >= 0 && j < len(s) && s[i] == s[j] {
        i--
        j++
    }
    
    return s[i+1:j]
}

func longestPalindrome2(s string, centerL, centerR int) string {    
    i, j := centerL, centerR
    for i >= 0 && j < len(s) && s[i] == s[j] {
        i--
        j++
    }
    
    return s[i+1:j]
}

精简、合并一些代码

Code Block
languagego
func longestPalindrome(s string) string {
    result := ""
    
    for i := 0; i < len(s); i++ {
        ps := palindrome(s, i, i)
        if len(ps) > len(result) {
            result = ps
        }
        
        ps = palindrome(s, i, i+1)
        if len(ps) > len(result) {
            result = ps
        }
    }
    
    return result
}

// 在 s 中寻找以 s[centerL] 和 s[centerR] 为中心的最长回文串
func palindrome(s string, centerL, centerR int) string {    
    i, j := centerL, centerR
    for i >= 0 && j < len(s) && s[i] == s[j] {
        i--
        j++
    }
    
    return s[i+1:j]
}

进阶解法Manacher 算法